Answer to Q86
What are the three consecutive integers whose sum are equal to 93?
Let the first integer be x. The consecutive integers will then be x+1 and x+2.
So, x + (x+1) + (x+2) = 93
x + x+1 + x+2 = 93
3x + 3 = 93
3x = 93 - 3
3x = 90
x = 90 ÷ 3
x = 30
So, first integer is 30.
Answer: 30, 31, 32
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