140. Program to find day on a particular date

#include<stdio.h>

int isLeapYear(int year){
if(year%4==0){
if(year%100==0 && year%400!=0){
return 0;
}
else{
return 1;
}
}
else{
return 0;
}
}

int main() {
int year;
int refYear=1600, leap=0;
int diff, totalDays,day,month, oddDays;
int lYear[]={3,1,3,2,3,2,3,3,2,3,2,3};
int nYear[]={3,0,3,2,3,2,3,3,2,3,2,3};
char week[7][10]={"sunday",
"monday",
"tuesday",
"wednesday"
,"thursday"
,"friday",
"saturday"};
printf("Enter a date between 1600 to 3000\n");
scanf("%d%d%d",&day,&month,&year);
diff = year - refYear;
while(refYear < year){
if(isLeapYear(refYear))
leap++;
refYear++;
}
totalDays = leap*366 + (diff-leap)*365;
oddDays = totalDays%7;

if(isLeapYear(year)){
for(int i=0;i<month-1;i++){
oddDays+=lYear[i];
}
oddDays+=day%7;
}
else{
for(int i=0;i<month-1;i++){
oddDays+=nYear[i];
}
oddDays+=day%7;
}
printf("Day on %d/%d/%d ",day,month,year);
printf("%s",week[(5+oddDays)%7]);
return 0;
}
#program_by : @Vecto_r

C Language 👨‍💻

140. Program to find day on a particular date

#include<stdio.h>

int isLeapYear(int year){
if(year%4==0){
if(year%100==0 && year%400!=0){
return 0;
}
else{
return 1;
}
}
else{
return 0;
}
}

int main() {
int year;
int refYear=1600, leap=0;
int diff, totalDays,day,month, oddDays;
int lYear[]={3,1,3,2,3,2,3,3,2,3,2,3};
int nYear[]={3,0,3,2,3,2,3,3,2,3,2,3};
char week[7][10]={"sunday",
"monday",
"tuesday",
"wednesday"
,"thursday"
,"friday",
"saturday"};
printf("Enter a date between 1600 to 3000\n");
scanf("%d%d%d",&day,&month,&year);
diff = year - refYear;
while(refYear < year){
if(isLeapYear(refYear))
leap++;
refYear++;
}
totalDays = leap*366 + (diff-leap)*365;
oddDays = totalDays%7;

if(isLeapYear(year)){
for(int i=0;i<month-1;i++){
oddDays+=lYear[i];
}
oddDays+=day%7;
}
else{
for(int i=0;i<month-1;i++){
oddDays+=nYear[i];
}
oddDays+=day%7;
}
printf("Day on %d/%d/%d ",day,month,year);
printf("%s",week[(5+oddDays)%7]);
return 0;
}
#program_by : @Vecto_r

hottg.com/C_Codings/202

226.9K viewsjeNiSh, Jan 30, 2021 at 20:38